find the volume, the lateral surface area ,the total surface area and the diagonal of a cube each of whose edges measures 9 cm (take underroot 3=1.73)
Answers
GIVEN:
Edge of the cube = 9cm
TO FIND:
LSA, TSA, Volume and diagonal of the cube
SOLUTION:
Lateral surface area of cube = 4a²
= 4(9)²
= 4(81)
= 324 cm²
Total surface area of cube = 6a²
= 6(9)²
= 6(81)
= 486cm²
Volume of cube = a³
= (9)³
= 729cm³
Diagonal of cube = a√3
= 9√3
= 9 × 1.73
= 15.57cm
Therefore,
LSA of cube = 324cm²
TSA of cube = 486cm²
Volume of cube = 729cm³
Diagonal of cube = 15.57 cm.
GIVEN :
- Edge of the cube = 9 cm.
TO FIND :
- Volume of cube.
- Lateral surface area of cube.
- Total surface area of cube.
- Diagonal of cube.
SOLUTION :
Formulas used :-
★Volume of cube = a³
★LSA of cube = 4a²
★TSA of cube = 6a²
★ Diagonal of cube=a√3
[ Where a = side of cube]
________________________
Volume of cube = a³
→ Volume of cube=(9)³ cm³
→ Volume of cube = 729 cm³
______________________
LSA of cube = 4a²
→LSA of cube= 4(9)² cm²
→LSA of cube=324 cm²
______________________
TSA of cube= 6a²
→TSA of cube=6(9)²cm²
→ TSA of cube = 486 cm²
______________________
Diagonal of cube = a√3
→Diagonal of cube= 9× 1.73 cm
→Diagonal of cube= 15.57 cm.
______________________
Therefore, Volume of cube is 729 cm³ , LSA of cube is 324 cm² , TSA of cube is 486 cm² and Diagonal of cube is 15.57 cm.
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