Question

Find the wait of calcium carbonate required to prepare 0.24M solution from 2 litres normality formula is used.(and:20grams)​

Answer 1

Answer:

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Explanation:

Semi - normal mean

Normality =0.5 N

Now normality =Volume of solutionno. of moles× n factor

n− factor of sodium Carbonate =3

{Na2CO3⟶2Na++CO32−}

Volume of solution =500 ml

                                =0.5 L

Now,

Normality =0.5 N

⇒0.5no. of moles×3=0.5

⇒ no. of moles =30.5×0.5=30.25

weight = molar mass × no. of moles 

          =(23×2+12+3×16)×30.25

          =(46+12+48)×30.25

          =106×30.25=653

                                     =8.833 g