Find the wave length and frequency. (Given, speed: 330 m/sec and amplitude = 2m)
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Answer:
Correct option is C)
Explanation:
V=330m/s
f=110Hz Amplitude =0.05m
Equation of wave =Asin(ωt±km)
k=
v
ω
=
v
2nf
=
330
2π×110
=
3
2π
ωt=2πft=2π×110t
∴ Equation is 0.05sin(2π×110t±
3
2π
x)
=0.05sin2π(110t±
3
x
)
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