Question

Find the wavelength of a proton accelerated by a potential difference of 50V

Answer 1

Answer:4.14 armstrong

Explanation:

we know,

lambda=h/p=h/root(2mpv)                               _____1

where,

m=1.6*10^-27kg

p=1.6*10^-19

v=50v

therefore, put the value in above equation 1 u'll get the answer