Question

Find the wavelength of an electron accelerated through a potential difference of 1 Volt
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Answer 1

Answer:

1 Answer. The de Broglie wavelength λ=1.23 x 10−9m . If a charge of 1 Coulomb is moved through a potential difference of 1 Volt then 1 Joule of work is done. This is how the Volt is defined.

Explanation:

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Answer 2

Explanation:

accelarating potential. V= 1v

wavelength is

lemda = h/p

= 1.227/√v nm

= 1.227/√1 nm

=1.23 nm

1.23 ×10 to the power minus 19

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