Question

find the wavelength of light having frequency 6×10¹⁵ Hz in (A⁰) ​

Answer 1

Answer:

HERE IS YOUR ANSWER

The energy of photon is

E=hν=6.626×10

−34

Js×3×10

15

m/s

=1.988×10

−18

J

(ii) The energy of photon is

E=

λ

hc

=

0.50×10

−10

m

6.626×10

−34

Js×3×10

8

=3.98×10

−15

s

Answer 2

Given

Frequency = 6 x 10¹⁵ Hz

To Find

Wavelength

Solution

We know that

$\sf \longrightarrow \lambda=\dfrac{c}{v}$

Here

• λ = Wavelength
• c = Speed of light
• v = Frequency

Units

• λ = metre (m)
• c = metres per second (m/s)
• v = Hertz (Hz) or seconds (s)

According to the question

We are asked to find the wavelength

Therefore

We must find "λ"

Given that

Frequency = 6 x 10¹⁵ Hz

Hence

• v = 6 x 10¹⁵ Hz

We know that

• c = 3 x 10⁸ m/s

Substituting the values

We get

$\sf \longrightarrow \lambda=\dfrac{3 \times 10^{8}}{6 \times 10^{15}} \ m$

On further simplification

We get

$\sf \longrightarrow \lambda=\dfrac{1}{2} \times 10^{8-15} \ m$

Therefore

$\sf \longrightarrow \lambda=0.5 \times 10^{-7} \ m$

Hence

$\sf \longrightarrow \lambda=5 \times 10^{-8} \ m$

According to the question

We are asked to find the wavelength in Angstrom (A⁰)

We know that

1 metre = 10¹⁰ A⁰

Hence

5 x 10⁻⁸ m = 500 A⁰

Therefore

λ = 500 A⁰