Question

Find the wavelength of the emitted radiation when electrons and holes in this semiconductor recombine directly. Here, the band gap for an alloy of semiconductor is 1.98 eV

Answer 1

Answer:

Wavelength emitted due to radiation is given as

$\lambda = 6.25 \times 10^{-7} m$

Explanation:

As we know that the potential of the band gap is given as

$E = 1.98 eV$

now we know that the electron hole will combine and it gives its whole potential energy in form of photons

so we have

$E = \frac{hc}{\lambda}$

now we have

$1.98(1.6 \times 10^{-19}) = \frac{(6.6 \times 10^{-34})(3 \times 10^8)}{\lambda}$

$\lambda = 6.25 \times 10^{-7} m$

#Learn

Topic : Photon wavelength

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