Find the wavelength of the first line in the lyman series
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1
Explanation:
The wavelength of the first line of lyman series for hydrogen atom is equal to that of the second line of balmer series for a hydrogen like ion. the atomic number z of hydrogen like ion
For 1st line in Balmer series n1 =2,n2=3 1/λ1= 109678[ 1/n1 2 -1/n22 ]
Answered by
1
Answer:
1216A^o
Explanation:
1/lambda=Rb(1/1-1/4)
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