Find the weight of a 1 gram object at the earth's surface? With solution
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Weight of an object on the surface of earth is just the force exerted by the object on earth.
We know that F = ma
So, Weight = m × a
=> weight = m × g (g = acceleration due to gravity)
For calculating weight in Newton, the mass should be in kg and the acceleration should be in m/s²
Given mass = 1 gram = 0.001 kg
Taking g as 10 m/s² we get,
weight = 0.001 × 10
=> weight = 0.01 Newton.
Or taking g as 9.8 m/s², we get
weight = 0.001 × 9.8
=> weight = 0.0098 Newton.
We know that F = ma
So, Weight = m × a
=> weight = m × g (g = acceleration due to gravity)
For calculating weight in Newton, the mass should be in kg and the acceleration should be in m/s²
Given mass = 1 gram = 0.001 kg
Taking g as 10 m/s² we get,
weight = 0.001 × 10
=> weight = 0.01 Newton.
Or taking g as 9.8 m/s², we get
weight = 0.001 × 9.8
=> weight = 0.0098 Newton.
Answered by
1
weight w = mass * gravity
g=10m/s
w=0.001kg*10
w=0.01N
g=10m/s
w=0.001kg*10
w=0.01N
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