find the weight of a body at a height of equal to radius of earth the weight of body on the surface of earth is 200n
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Acceleration due to gravity at a depth d from surface of earth
g
′
=g(1−
R
d
) ....(1)
Where g = acceleration due to gravity at earth's surface
Multiplying by mass 'm' on both sides of (1)
⟹mg
′
=mg(1−
R
d
)Here,(d=
2
R
)
=200(1−
2R
R
)=
2
200
=100N
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Answer:
268 million this is the correct answer
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