Question

Find the weight of a hollow cylindrical lead pipe 28 cm long and 1/2 cm thick. It's internal diameter is 8 cm . Weight of 1 cmcube of lead is 11.4g . [pie=22/7].

Answer 1

Volume of cylinder=pie*r^2*h

=22/7*4*28

=352cm cube.

352+1/2cm= 705/2(Thickness has to be added with volume.)

weight of 1cmcube of lead=11.8g

weight of 705/2cmcube of lead=705/2*11.8

5959.5g=5.95kg

Hope it helps you :)

Answer 2

calculate the value of 11•4 ×23980