find the weight of a hollow cylindrival lead pipe 28 cm long and 1/2 cm thick . Its internal diameter is 8 cm . Weight of 1 cm cube of lead is 11.4 g ( pi = 22 /7 )
Answers
Answered by
2
r=8÷2=4cm
h=28cm
R=8÷2+1/2=4.5
volume of pipe=volume of outer pipe- volume of inner pipe
=πR²h-πr²h
=22/7×4.5×4.5×28-22/7×4×4×28
=374cm³
since weight of 1cm³is 11.4g
374×11.4
=4263.6
Similar questions