Question

Find the weight of a lead pipe 5.6 m long , if the external diameter of the pipe is 3.4 cm and the thickness of lead is 2 mm and 1 cm^3 of lead weight 10 g .​

Answer 1

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⇛External diameter of the pipe = 3.4 cm.

⇛External radius ( R ) of the pipe = 1.7 cm.

⇛Thickness of the pipe = 2mm = 0.2 cm.

⇛Internal radius = External radius - Thickness

= 1.7 - 0.2 = 1.5 cm.

⇛Length of the pipe (h) = 5.6 m = 560 cm.

⇛Volume of lead = External volume - Internal Volume .

$= \pi \: R^{2}h - \pi \: r^{2}h = \pi(R^{2} - r^{2})h = \frac{22}{7} \times [(1.7)^{2} - (1.5)^{2}] \times 560 \\ = \frac{22}{7} \times 0.64 \times 560 = 1126.4 \: cm^{2}$

⇛Mass = Volume × Density = 1126.4 × 10 = 11264 gm .

= 11264 / 1000 Kg = 11.264 kg .

Hence , Mass is 11.264 kg .

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Answer 2

Answer:

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