Physics, asked by OldDaemon29, 11 hours ago

Find the weight of a meter scale balanced at 30 cm such that two weights one of 80 gf and 10 gf are suspended at 5 cm mark and 40 cm mark respectively
10 gf
105 gf
25 gf
32.5 gf

Answers

Answered by nirman95
5

The metre scale is balanced at 30 cm such that two weights one of 80 gf and 10 gf are suspended at 5 cm mark and 40 cm mark.

  • Always remember that weight of the scale will act at the centre of mass (i.e. at the middle) at 50 cm mark.

  • Also, the distance of force acting on the scale will be calculated from the 30 cm mark.

Now, since the scale is at rotational equilibrium, you can say:

 \sum( \tau) = 0

 \implies  \{80 \times (30 - 5) \} = \{10 \times (40 - 30) \} +  \{w \times (50 - 30) \}

 \implies  \{80 \times 25 \} = \{10 \times 10\} +  \{w \times 20 \}

 \implies  2000 =20w + 100

 \implies  20w  = 1900

 \implies  w  = 95 \: gf

So, weight of scale is 95 gf.

Answered by krishworthy
0

Answer:

32.5gf is give n as the ans

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