Find the weight of a metre scale balanced at 30cm mark such that two weights one of 80gf and 10gf are suspended at 5cm mark and 40cm mark respectively.
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Find the weight of a metre scale balanced at 30cm mark such that two weights one of 80gf and 10gf are suspended at 5cm mark and 40cm mark respectively .
Solution :
The metre scale is balanced at 30 cm such that two weights one of 80 gf and 10 gf are suspended at 5 cm mark and 40 cm mark.
Always remember that weight of the scale will act at the centre of mass (i.e. at the middle) at 50 cm mark.
Also, the distance of force acting on the scale will be calculated from the 30 cm mark.
Now, since the scale is at rotational equilibrium, you can say:
\sum( \tau) = 0∑(τ)=0
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m = 1900 / 20 = 95 gf
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