Physics, asked by annanya5645, 9 months ago

find the weight of a person at depth R/3 below the earths surface ,if weight on surface is 100N.

Answers

Answered by manujgupta46

3

Answer:

g' = g ( 1-d/R)

mg' = mg (1- d/R)

= 100 ( 1 - R/3×1/R)

= 100×2/3

=200/3 N

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