Find the weight of a solid cylinder of radius 10.5 cm and height 60 cm, if the material of the cylinder weighs 5 grams per cu. cm.
Answers
Answer:
Step-by-step explanation:
volume of cylinder = πr²h
=22/7×10.5×10.5×60
=22×1.5×630
=22×945
=20790 cm³
density = mass / volume
= 5 g/cm³/20790 cm³
=5 g/20790
=0.000240500241 grams
weight = density ×volume
=2i
Answer:
weightofthesolidcylinder
\green { = 103.95 \:kg }=103.95kg
Step-by-step explanation:
Dimensions \: of \: a \: cylinder :Dimensionsofacylinder:
Radius (r) = 10.5 \:cmRadius(r)=10.5cm
Height (h) = 60\:cmHeight(h)=60cm
\boxed { \pink {Volume \: of \: a \: cylinder = \pi r^{2}h }}
Volumeofacylinder=πr
2
h
V = \frac{22}{7} \times (10.5)^{2}\times 60V=
7
22
×(10.5)
2
×60
= \frac{22}{7} \times 10.5\times10.5\times 60=
7
22
×10.5×10.5×60
= 22 \times 1.5\times10.5\times 60=22×1.5×10.5×60
= 20790\: cm^{3}=20790cm
3
/* According to the problem given,
1\:cm^{3} \: material \: weight = 5 \:gm1cm
3
materialweight=5gm
\begin{lgathered}20790 \:cm^{3} \: cylinder \: material \: weight \\= 5 \times 20790 \\= 103950\:gm\\= 103.95\:kg\end{lgathered}
20790cm
3
cylindermaterialweight
=5×20790
=103950gm
=103.95kg
Therefore.,
\red { weight \: of \: the \: solid \: cylinder }weightofthesolidcylinder
\green { = 103.95 \:kg }=103.95kg