Math, asked by mohsin991, 1 year ago

find the weight of a solid iron cylinder of height 25cm and the radius of the base 14 cm if 1cc of iron weighs 7.8g​

Answers

Answered by Fatimakincsem
15

Answer:

120071.67 g

Step-by-step explanation:

The volume V of a solid iron cylinder with

radius r = 14cm, is the area of the base B times the height h = 25cm

V = baseArea x height

V = πr² x h

V = π14² (25)

V = 4900π

since 1cc = 7.8g

so

  4900π = 7.8 x 4900π

              = 38220π g

              = 120071.67 g

Weight of a solid iron cylinder of height 25 and the radius of the base 14 is 120071.67 g

Answered by HMD1234
3

Answer:

120.12 kg

Step-by-step explanation:

volume × 7.8

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