find the weight of a solid iron cylinder of height 25cm and the radius of the base 14 cm if 1cc of iron weighs 7.8g
Answers
Answered by
15
Answer:
120071.67 g
Step-by-step explanation:
The volume V of a solid iron cylinder with
radius r = 14cm, is the area of the base B times the height h = 25cm
V = baseArea x height
V = πr² x h
V = π14² (25)
V = 4900π
since 1cc = 7.8g
so
4900π = 7.8 x 4900π
= 38220π g
= 120071.67 g
Weight of a solid iron cylinder of height 25 and the radius of the base 14 is 120071.67 g
Answered by
3
Answer:
120.12 kg
Step-by-step explanation:
volume × 7.8
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