Question

Find the weight of a solid rectangular iron piece of size 10 X 40 X 50 if 1 cm cube of iron weight 8 grams

Answer 1

Answer:

160 lg is the required answee

Step-by-step explanation:

☆

➾Length = 50 cm

➾Breadth = 40 cm

➾Height = 10 cm

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♦ Volume = 50 cm x 40 cm x 10 cm = 20000 cm³

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♣ Given that,

the weight of 1 cm³ of iron is 8 gm.

The weight of the given piece of iron = 20000 x 8 gm

= 160000 gm

= 160 x 1000 gm

= 160 kg

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The weight of the solid rectangular iron piece is 160 kg.