Find the weight of a solid rectangular iron piece of size 10 X 40 X 50 if 1 cm cube of iron weight 8 grams
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Answer:
160 lg is the required answee
Step-by-step explanation:
☆
➾Length = 50 cm
➾Breadth = 40 cm
➾Height = 10 cm
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♦ Volume = 50 cm x 40 cm x 10 cm = 20000 cm³
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♣ Given that,
the weight of 1 cm³ of iron is 8 gm.
The weight of the given piece of iron = 20000 x 8 gm
= 160000 gm
= 160 x 1000 gm
= 160 kg
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The weight of the solid rectangular iron piece is 160 kg.
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