Question

Find the weight of a solid rectangular iron piece of size 50 cm x 40 cm x 10 cm, if 1 cm³of iron weighs 8 gm.

Answer 1

☆ ${ \underline\textbf{Given Dimensions :}}$



➾Length = 50 cm

➾Breadth = 40 cm

➾Height = 10 cm





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♦ Volume = 50 cm x 40 cm x 10 cm = 20000 cm³



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♣ Given that,

the weight of 1 cm³ of iron is 8 gm.

The weight of the given piece of iron = 20000 x 8 gm

= 160000 gm

= 160 x 1000 gm

= 160 kg


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The weight of the solid rectangular iron piece is ${ \underline\textbf{160 kg}}$.

Answer 2

Answer:

160 kg

Step-by-step explanation:

solid rectangular iron piece of size 50 cm x 40 cm x 10 cm

volume =50x40x10 cm^3

             =20000 cm^3

1 cm³of iron weight  =  8 gm.  

total weight  =20000x 8  gm

                    =160000 gm

                    =160 x1000 gm

                      =160 x 1kg

                     =160 kg