Math, asked by ushapacharanr, 20 days ago

find the weight of an iron cylinder of height 20 cm and radius of the base 10 cm if 1 cm of iron 8 g​

Answers

Answered by yashshukla0608
0

Answer:

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Answered by shabeehajabin
1

Answer:

The weight of the iron cylinder is 50.24 kg.

Step-by-step explanation:

It is given that the height of the cylinder is 20 cm, and the radius of the base is 10 cm.

The weight of the cylinder can be found by calculating the volume of the cylinder. The formula for the volume of the cylinder is given as follows,

         V=\pi r^2h

Now substitute the values to find the volume.

      h = 20 cm

       r = 10 cm

       \pi=3.14

 ∴    V=3.14\times 10^2\times 20

       V= 6280\ cm^3

1 cubic centimeter of iron is 8 grams. Then the weight of the cylinder = 6280\times 8= 50240\ g

We know that 1000 g = 1 kg

∴ Weight = \dfrac{50240}{1000} = 50.24\ kg

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