Find the weight of an object at a height of 3200 m above the Earth's surface. the weight of the object at the surface of earth is 200 Newton and the radius of earth is 6400 km.
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F = GMm
R²
M is the mass of the Earth m is the mass of the object
R is the radius of the earth =6400km(given)
When object is kept on surface.
W=F=GMm= 20 N
R²
When object is lifted to a certain height=R' = R+h = 2R
h = R = 6400 km
Now we have weight of the object is
W' = F' = GMm
(2R)²
W' = (1/4).(GMm)
R²
=W
4
Now the weight of the object will be
weight=20
4
W=5N
Hope it helps
R²
M is the mass of the Earth m is the mass of the object
R is the radius of the earth =6400km(given)
When object is kept on surface.
W=F=GMm= 20 N
R²
When object is lifted to a certain height=R' = R+h = 2R
h = R = 6400 km
Now we have weight of the object is
W' = F' = GMm
(2R)²
W' = (1/4).(GMm)
R²
=W
4
Now the weight of the object will be
weight=20
4
W=5N
Hope it helps
singhranjana194:
Y C/P
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