Question

Find the weight of an object of mass 12 kg on the
surface of a planet whose acceleration due to
gravity is half than that of the Earth.
(A) 60.2 N
(B) 58.8 N
(C) 74.5 N
(D) 12 N​

Answer 1

Answer:

(B) 58.8 N

Explanation:

Given:

• Mass (m) = 12 kg
• $\sf{g_{planet}\:=\:\dfrac{1}{2}\:g_{earth}}$

To find:

• Weight (W) = ?

Solution:

Let the acceleration due to gravity of planet = g'. We know, that acceleration due to gravity of earth (g) = 9.8 m/s²

So, g' = ½ × 9.8.

$\:$

As we remember that,

$\star\boxed{\pink{\sf{Weight\:of\:an\:object\:=\:M\:\times\:g}}}$

$\:$

$\Longrightarrow\:\sf{Weight\:=\:12\:\times\:\dfrac{1}{2}\:\times\:9.8}$

$\:$

$\Longrightarrow\:\sf{Weight\:=\:\cancel{12}\:\times\:\dfrac{98}{\cancel{2}\:\times\:10}}$

$\:$

$\Longrightarrow\:\sf{Weight\:=\:\dfrac{6\:\times\:98}{10}}$

$\:$

$\Longrightarrow\:\sf{Weight\:=\:\dfrac{588}{10}}$

$\Longrightarrow\:\sf{\underline{\underline{\therefore\:Weight\:of\:object\:=\:58.8\:N}}}$

Answer 2

GiveN :-

• Mass (m) = 12 kg

• $\sf{g_{planet}\:=\:\dfrac{1}{2}\:g_{earth}}$

To FinD :-

• Weight ( w )

SolutioN :-

Let acceleration due to gravity of planet = g'.

We know, that acceleration due to gravity of earth (g) = 9.8 m/s²

So, g' = ½ × 9.8

As we remember that

$\longrightarrow\boxed{\green{\bf{Weight\:of\:an\:object\:=\:M\:\times\:g}}} \\ \\ \longrightarrow\:\sf{Weight\:=\:12\:\times\:\dfrac{1}{2}\:\times\:9.8} \\ \\ \longrightarrow\:\sf{Weight\:=\:\cancel{12}\:\times\:\dfrac{98}{\cancel{2}\:\times\:10}} \\ \\ \longrightarrow\:\sf{Weight\:=\:\dfrac{6\:\times\:98}{10}} \\ \\ \longrightarrow\:\sf{Weight\:=\:\dfrac{588}{10}}$

$\large \therefore\:\underline {\bf\blue{ Weight\:of\:object\:=\:58.8\:N}}$