Find the weight of cube of mild steel of 14 cm side with its density being 7.8 gms/cc-
Answers
Answered by
1
Volume of the mild steel = 14x14x14 = 2744
Mass = Density x Volume = 7.8 x 2744 = 21403.2 g = 21.4032 kg
Assuming that the force of gravity, g = 10N/kg
The weight of the mild steel = 10 x 21.4032 = 214.032 N
Mass = Density x Volume = 7.8 x 2744 = 21403.2 g = 21.4032 kg
Assuming that the force of gravity, g = 10N/kg
The weight of the mild steel = 10 x 21.4032 = 214.032 N
Answered by
0
According to question
Side of cube = a = 14 Cm
Also
Density of cube D = 7.8 gms / cc
According to question
Density = Mass / volume
thus
Mass = Density * Volume
M = 7.8 * 14^3
M = 21403.2 gm
thus weight of cube is 21403.2 gm
Side of cube = a = 14 Cm
Also
Density of cube D = 7.8 gms / cc
According to question
Density = Mass / volume
thus
Mass = Density * Volume
M = 7.8 * 14^3
M = 21403.2 gm
thus weight of cube is 21403.2 gm
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