Question

find the weight of the body (in attachment) suspended by the string, It's tension developed in the string is 60 N.Also draw the arrangement in order to show the direction of weight.

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Answer 1

Answer:

since the body shown in the above figure is in equilibrium (static) therefore its weight got balanced by the Tension in the rope,therefore weight of the body is

F=m×a over here a is the acceleration due to gravity

therefore m=F/a i.e 6kg wt.

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Answer 2

Answer:

Tension in the string balances the weight of the suspended block i.e. T=W

Balancing force in vertical direction, on the point on right side,

T=60sin45

0

=60×0.707=42.43N

∴ W=T=42.43N

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