find the weight of the hollow cylinder lead pipe 28 cm long and 0.5 CM thick its inner diameter is 8 cm weight of 1 cm cube of lead is 11.4 gram
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height of hollow cylinder lead pipe=28cm
inner diameter of hollow cylinder lead pipe=8cm
inner radius of hollow cylinder lead pipe=diameter/2=8/2=4cm
thickness of hollow cylinder lead pipe=0.5cm
exterior radius of hollow cylinder lead pipe=inner radius+thickness=4+0.5)cm=4.5cm
volume of hollow cylinder lead pipe=volume of external cylinder-volume of inner cylinder
=(pia×R^2×h)-(pia×r^2×h)
=pia×h(R^2-r^2)
=(22/7)×28[(4.5)^2-4^2]
=22×4(20.25-16.00)
=(88×4.25)cm^3
=374cm^3
weight of 1cm^3 of lead=11.4g
weight of 374cm^3 of lead=(374×11.4)g
=4263.6g
inner diameter of hollow cylinder lead pipe=8cm
inner radius of hollow cylinder lead pipe=diameter/2=8/2=4cm
thickness of hollow cylinder lead pipe=0.5cm
exterior radius of hollow cylinder lead pipe=inner radius+thickness=4+0.5)cm=4.5cm
volume of hollow cylinder lead pipe=volume of external cylinder-volume of inner cylinder
=(pia×R^2×h)-(pia×r^2×h)
=pia×h(R^2-r^2)
=(22/7)×28[(4.5)^2-4^2]
=22×4(20.25-16.00)
=(88×4.25)cm^3
=374cm^3
weight of 1cm^3 of lead=11.4g
weight of 374cm^3 of lead=(374×11.4)g
=4263.6g
zapthius:
thank you so much
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