Question

Find the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10 of the earth’s pull. Show all work.

Answer 1

Explanation:

force= mg

on earth weight= force= mg, where g= earth gravitaional acceleration

but as per your question

on the planet having gravity 1/10th of earth is

weight= force=mg/10

Answer 2

Gravitational Force:

Explanation:

• Gravitational force is a force exerted by the earth surface  on all objects on it.

• Weight of an object on earth surface is equal to the  product of

        mass of the object and gravity of earth.

• Weight of object on earth  = $\textrm {mass of object \times gravity of earth Gravity of earth is 9.807 m/s².}$$\textrm{Mass of object} \times \textrm{gravity of earth}$

        Gravity of earth is $9.807 \ m/s^2.$

• Weight of object on earth = mass of object × 9.807

• Weight of the object on a planet where the gravitational attraction reduced to 1/10 of the earth's pull.

• Weight of object on another planet      $\bf=\frac{mass \times 9.8}{10}$

       $\textrm{Weight of object on another planet} =\textrm{mass of the object (approx.)}$

So, weight of the object is approx. equal to the mass of the object.