Question

find the whole cube of :-
(2x+3y)³​

Answer 1

Answer:

8x^3+36x^2y+54xy^2+27y^3

Answer 2

Answer:

$\bold{(2x+3y)³}$

$\large{ \pink{ \boxed{ \bold{ \green{Formula :-}}}}}$

$\bold{ \scriptsize{(a + b)³ = a³ + 3a²b + 3ab³ + b³}}$

$\bold{a=2x \: , \: b = 3y}$

$\bold{ \scriptsize{(2x)^{3} + 3(2x)^{2}(3y) + 3(2x)(3y) ^{2} + (3y)^{3} }}$

$\bold{8 {x}^{3} + 36x^{2} y + 54x {y}^{2} + 27y ^{3} }$

I hope it is helpful