Question

Find the whole number roots of the equation 2x^2-7x+6=0​

Answer 1

Answer:

Hey mate! Here's your answer:

Step-by-step explanation:

2x² - 7x + 6 = 0

2x² - 3x - 4x + 6 = 0

x(2x - 3) - 2(2x - 3) = 0

(x - 2)(2x - 3) = 0.

x - 2 = 0

x = 2.

2x - 3 = 0

2x = 3

x = 3/2.

So the whole number root of this Equation is 2 and the other root is 3/2.

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Answer 2

Answer:

x=2

Step-by-step explanation:

2x^2 - 7x + 6=0

2x^2 - 3x - 4x +6 =0

x (2x - 3) - 2 (2x -3) =0

( x - 2) (2x - 3) =0

x - 2 =0 2x - 3 =0

x = 2 2x = 3

x= 3/2

whole number root is x = 2

( x=3/2 is not a whole number)