Find the whole number such that twice its square added to itself makes 10.
Answers
Answer:
2
Step-by-step explanation:
Let the number be x
2x^2 + x = 10
2x^2 +x -10 = 0
2x^2 -4x +5x -10 = 0
2x ( x -2) +5( x-2) = 0
( 2x +5) ( x-2) = 0
x = - 5/2 OR 2
Answer = 2
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Given : Twice the square of a whole number added to itself makes 10
To find : The said whole number.
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the said whole number)
Let, the whole number = x
So, the square of the whole number :
= x²
According to the data mentioned in the question,
(2 × x²) + x = 10
2x²+x-10 = 0
2x²-4x+5x-10 = 0
2x(x-2) + 5(x-2) = 0
(x-2) (2x+5) = 0
Either,
(x-2) = 0
x = 2
Or,
(2x+5) = 0
2x = -5
x = -5/2
As, the said number is a whole number, so we will omit x = -5/2
Hence, the whole number is 2