Question

find the whole number which when decreased by 20 is equal to 69 times the reciprocal of the number

Answer 1

Let the number = x
Reciprocal = 1/x

ATQ

x -20 = 69/x

x - 69/x = 20

x^2 - 69 = 20x

x^2 -20x  -69 = 0

x^2 -23x + 3x -69 = 0

x(x-23) + 3(x-23) = 0

(x-23)*(x+3) = 0

>> x= 23, -3

x= 23 is the answer as x is whole number.

Answer 2

Step-by-step explanation:

let let the number be x

let let the reciprocal reciprocal of the number 1/x

according to question,

x-20=69/x

x-69=20

x^2-69x-69=0

x^2-23x+3x-69=0

x(x-23)+3(x-23)=0

therefore, x=23.

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