find the width of carpet if its length is 12 feet and it has a diagonal of length 20 feet
Answers
Answered by
6
Hey there
Here is your answer > >
A carpet is of rectangular shape
d^2= l^2+b^2
20^2= l^2+12^2
400-144=l^2
256=l^2
l=Root 256
l=16 foot
hope that helps
Here is your answer > >
A carpet is of rectangular shape
d^2= l^2+b^2
20^2= l^2+12^2
400-144=l^2
256=l^2
l=Root 256
l=16 foot
hope that helps
happykumarjain:
sorry but the answer is 16 feet
Answered by
9
Given Length of the carpet = 12 feet and Diagonal = 20 feet.
Let the width of the carpet = 'x' feet.
Now,
We can use Pythagoras theorem to find the width of the carpet.
⇒ Diagonal^2 = (Length)^2 + (Width)^2
⇒ (20)^2 = (12)^2 + (x)^2
⇒ 400 = 144 + x^2
⇒ 400 - 144 = x^2
⇒ 256 = x^2
⇒ √256 = x
⇒ x = 16.
Therefore, the width of the carpet = 16 feet.
Hope it helps!
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