Question

find the width of the rectangular whose area is 209 m² and length is 19 m​

Answer 1

$\huge \rm \underline \green {question} :$

find the width of the rectangular whose area is 209 m² and length is 19 m

$\huge \rm \underline \pink {answer }:$

we know that,

$area \: of \: the \: rectangle :l \times b$

let width be x

so finding width we must divide the length and area.

so ,

$\frac{area}{lenght} = \frac{209}{19} = 11$

thus,

$the \: width \: of \: the \: square \: is \: \\ \: 11m$

Answer 2

$\huge \fbox{Answer}$

$\large \underline{\underline{\frak{ \color{red}Given:}}}$

$\mapsto \sf{Area \: of \: rectangle=209 {m}^{2} }$

$\mapsto \sf{Length \: of \: rectangle=19m}$

$\large \underline{\underline{\frak{ \color{blue}To \: find:}}}$

$\leadsto \sf{Breadth \: of \: rectangle. }$

$\large \underline{\underline{\frak{ \color{indigo}Formula \: required:}}}$

${ \rightarrow\sf{Breadth \: of \: rectangle = \frac{Area \: of \: rectangle}{Length \: of \: rectangle} }}$

$\large \underline{\underline{\frak{ \color{indig}According \: to \: Question:}}}$

${ : : \implies\sf{Breadth \: of \: rectangle = \frac{Area \: of \: rectangle}{Length \: of \: rectangle} }}$

${ : : \implies\sf{Breadth \: of \: rectangle = \frac{209 {m}^{2} }{19m} }}$

${ : : \implies\sf{Breadth \: of \: rectangle = { \cancel{ \frac{209 {m}^{2} }{19m} }}}}$

${ : : \implies\sf{Breadth \: of \: rectangle = 11m }}$

$\bf{Hence,}$

${ : : \longmapsto\sf{Breadth \: of \: rectangle = 11m }}$