Question

find the work done by the force​

Answer 1

Answer:

Given:

A force vs Displacement graph has been provided.

To find:

Work done by the force.

Concept:

Work done is the amount of energy used to displace the body with the force.

Mathematically, we can say that :

$\huge{ \boxed{ \red{work = \displaystyle\int \: F \: dx}}}$

If a graph is provided , this integration can be considered as area under the F-x curve.

Calculation:

Work = Area of the Triangle

=> Work = ½ × base × height

=> Work = ½ × (14 - 2) × 60

=> Work = 12 × 30

=> Work = 360 Joule.

So final answer :

$\boxed{ \huge{ \green{ \sf{work = 360 \: joule}}}}$

Answer 2

$\huge \underline {\underline{ \mathfrak{ \green{Ans}wer \colon}}}$

As we know that :

$\large{\boxed{\sf{Work \: = \: F. dx}}}$

And the Graph is Provided with the Force-Displacement graph.

So,

$\implies {\sf{Work \: = \: Area \: under \: graph}}$

Take Area of the Triangle :

$\implies {\sf{Work \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Height}} \\ \\ \implies {\sf{Work \: = \: \dfrac{1}{2} \: \times \: (14 \: - \: 2) \: \times \: 60}} \\ \\ \implies {\sf{Work \: = \: \dfrac{1}{2} \: \times \: 12 \: \times \: 60}} \\ \\ \implies {\sf{Work \: = \: \dfrac{1}{2} \: \times \: 720}} \\ \\ \implies {\sf{Work \: = \: 360}} \\ \\ \underline{\sf{\therefore \: Work \:Done \: is \: 360 \: Joule}}$