Question

find the work done if time is 3,5 and the s=(4t^3+5t^4+5t) and the mass of the body is 4kg​

Answer 1

Given Mass m=4kg

Force F=(4i^+12t2j^)N

Initial velocity v=(2i^+j^+2k^)m/s

Magnitude of v=22+I2+I2=9=3m/s

Net force =∣∣∣∣(4i+∣∣∣∣2t2j^∣∣∣∣)N∣∣∣∣⇒ma=162+144t4⇒4a=41+9t4⇒a=1+9t4⇒dtdv=1+9t4⇒v=12+(3t2)2at(t=1)=4

Work = Force × displacement

=12.6×31=4J