Physics, asked by arvindmaravi462, 1 day ago

Find the work done in blowing a soap bubble of diameter 5.8 mm if the surface tension of soap solution is 2 x 10 4 N/m.

Answers

Answered by prkhprt001

0

Answer:

Explanation:

R1 = 0

R2 = 5.8mm or 0.0058m

S = 2x10^4 N/m

Work Done = S8π(R2^2 - R1^2)

= 2x10^4 x 8 x 3.14 x (0.0058^2 - 0)

16 joule

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