Question

find the work done in moving a charge of 10C in 10sec​

Answer 1

Need to FinD :-

• The work done .

$\red{\frak{Given}}\begin{cases}\textsf{ A charge of 10C is moving .}\\\textsf{ The time is 10s .}\end{cases}$

Here I would be taking Resistance as 10Ω , since resistance is not mentioned , without which the question is incomplete . So , we know the potential difference is defined as , ❛❛ the amount of work done in moving a unit positive charge from infinity to a certain point in an electric field. " . So here let's find the Voltage .

$\sf:\implies Voltage = (Current)(Resistance) \\\\\sf:\implies V = \dfrac{Q}{t}\times R \\\\\sf:\implies V = \dfrac{10C}{10s}\times 10 \\\\\sf:\implies V = 1 \times 10 V \\\\\sf:\implies \boxed{\pink{\frak{ Voltage = 10\ V }}}$

$\rule{200}2$

• Using the Formula of Work :-

$\sf:\implies Work = Charge \times Voltage \\\\\sf:\implies Work = 10C \times 10V \\\\\sf:\implies \boxed{\pink{\frak{ Work = 100\ Joules }}}$