Question

Find the work done in moving the charge of 10c through a resistance of 2ohm in 10sec

Answer 1

Answer:5V×10c=50J

Explanation:

Answer 2

To find:

The work done in moving the charge of 10c through a resistance of 2 ohm in 10 sec.

Calculation:

First of all , let us calculate the potential difference across which the charge is moving.

Let the potential difference be V :

$\rm \therefore\: V = current\times resistance$

$\rm = > \: V = i\times r$

$\rm = > \: V = \dfrac{charge}{time} \times r$

$\rm = > \: V = \dfrac{10}{10} \times 2$

$\rm = > \: V = 1 \times 2$

$\rm = > \: V = 2 \: volt$

Now , we know that : Potential difference is defined as the work done to transport a unit positive charge from one position to another in a electric field.

$\rm \therefore \: V = \dfrac{work}{charge}$

$\rm = > \: work = V \times charge$

$\rm = > \: work = 2 \times 10$

$\rm = > \: work = 20 \: joule$

So, work done is 20 Joules.

Hope It Helps.