Question

find the work done in raising mass of 200 mg through a height of 50 m?

Answer 1

mass (m) = 200mg = 0.2g = 2 × 10^(-4) kg

height raised(h) = 50m

We need work done.

Work done = force × displacement

Force =mg = 2×10^(-4) × 10 = 2 × 10^(-3) N

displacement = h = 50m

Work done = 2 × 10^(-3) × 50 = 100 × 10^(-3) = 0.1 Joule.

Work done is 0.1 Joule.

__________________

Shortcut:

Work done = change in total energy of the object.

There is no kinetic energy associated with it.

So Work done = change in Potential energy.

Change in PE = mgh = 2×10^(-4) × 10 × 50 = 0.1Joule

W = 0.1 J

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ĄNsWeR࿐}}}$

mass (m) = 200mg = 0.2g = 2 × 10^(-4) kg

height raised(h) = 50m

We need work done.

Work done = force × displacement

Force =mg = 2×10^(-4) × 10 = 2 × 10^(-3) N

displacement = h = 50m

Work done = 2 × 10^(-3) × 50 = 100 × 10^(-3) = 0.1 Joule.

Work done is 0.1 Joule.

__________________

Shortcut:

Work done = change in total energy of the object.

There is no kinetic energy associated with it.

So Work done = change in Potential energy.

Change in PE = mgh = 2×10^(-4) × 10 × 50 = 0.1Joule

W = 0.1 J

HOPE SO IT WILL HELP......