Question

Find the work done in trans ferring 20C charge between two points having a potential difference on 5v

Answer 1

Answer:

Explanation:

100J of work is done...

The work done when a unit charge is carried from “one point to another” is the potential difference.

V=\frac{1 J}{1 C}V=

1C

1J

\mathrm{V}=\frac{100}{20}V=

20

100

= 5 volts

Resistance is the property of any material to allow an electric current to pass through it or the opposing force of the material to electric flow.

The unit of resistance is ohms.

The formula for calculating resistance: R=\frac{v}{I}R=

I

v

where R is the ‘resistance’,

V is the ‘potential difference’,

I is the ‘current flowing’.

V= 5 volts

I = 2A

\mathrm{R}=\frac{5}{2}R=

2

5

= 2.5 ohms

Resistance = 2.5 ohms .

Answer 2

$\huge\bf\blue {Answer - }$

Find the work done in transferring 20C charge between two points having a potential difference on 5v.

Sol=

Given that,

• Q ( charge) = 20 C
• V ( Potential difference ) = 5V

We have to find -

• W ( amount of work done)

Formula Used here,

$\huge\boxed {W = Q \times V}$

W = 20 C × 5 V

W = 100 J

So ,the amount of work done is 100 joules (J)

_______________________________________________

Some more important formulae related to this topic -

$\huge\boxed { I = \frac{Q}{T}}$

___....

$\huge\boxed {V= \frac{W}{Q}}$

_.....

$\huge\boxed {V = IR \: (ohm's \: law)}$

Si units...

• Q (charge) ⟶ Coulomb (C)
• t (time) ⟶ Seconds
• I (current) ⟶ ampere (A)
• V (potential difference) ⟶ Volt (V)
• W (work done) ⟶ Joule (J)
• R ( resistance) ⟶ ohm ( Ω )