find the work done of a stretched copper wirev1m long and 2mm in dusmeter through 1cm given 12.5×10^10n/m^2
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Answer:
Young Modulus of Elasticity
Y=
Al
FL
F=
L
YAl
F=
2
2×10
11
×1×10
−6
×10
−3
×10
−1
F=100N
Work Done =
2
1
×100×1×10
−3
×10
−1
=0.005J
Work done = 5×10
−3
joule
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