Physics, asked by ifsazahoor9900, 4 months ago

find the work done of a stretched copper wirev1m long and 2mm in dusmeter through 1cm given 12.5×10^10n/m^2​

Answers

Answered by codroo80
1

Answer:

Young Modulus of Elasticity

Y=

Al

FL

F=

L

YAl

F=

2

2×10

11

×1×10

−6

×10

−3

×10

−1

F=100N

Work Done =

2

1

×100×1×10

−3

×10

−1

=0.005J

Work done = 5×10

−3

joule

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