find the work done required to stop a body of mass 10 kg travelling at 54 km/h.
Answers
Answered by
1
Answer:
w=f.s where f =ms n a=v/t so ans is 2250
Answered by
5
Answer:
Your answer is -1125Joule
Explanation:
here first convert 54 km into m/s by dividing it by 5by 18. then you'll get 15m/s.now ... ur final energy is 0 means half mvsq. is 0 and half musq.
w=0-1/2mu^²
=0-1/2×10×15^2
=0-2250/2
=0-1125
=-1125
u will get ans. with minus sign becoz it's a negative work...
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