Question

find the work done required to stop a body of mass 10 kg travelling at 54 km/h.

Answer 1

Answer:

w=f.s where f =ms n a=v/t so ans is 2250

Answer 2

Answer:

Your answer is -1125Joule

Explanation:

here first convert 54 km into m/s by dividing it by 5by 18. then you'll get 15m/s.now ... ur final energy is 0 means half mvsq. is 0 and half musq.

w=0-1/2mu^²

=0-1/2×10×15^2

=0-2250/2

=0-1125

=-1125

u will get ans. with minus sign becoz it's a negative work...