Find the work done when a force of 5N is applied at an angle of 600 and the object is displaced through a distance of 10m(Cos 600 = 0.5)
Answers
Answered by
2
Answer:
Work done in fruit case =F.S.cosθ
=10×2×cos60
10J
Work done in second case is same as 10J=FScosθ
⇒F×2×cos30=10
F=
3
10
N
Similar questions