Find the work required to make a soap bubble of radius 0.02m?Surface Tension of soap solution=0.03N/m.
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7
⇒Radius of the soap bubble= 0.02 m
∛
⇒Surface tension of the soap solution=0.03N/m
⇒Let us find the surface area.
so ,
⇒surface area = 4(π) r²
.⇒=4×22/7×(0.2 )²
⇒No .of surface area of the soap bubble = 2 ( Outer and inner area )
⇒Surface area is given as TΔS per surface
⇒Let us next find the total surface area =2 (TΔS)
⇒E = 2 ×0.03 × 4×22/7 × (0.2 )² Joule.....is the ans.
Answered by
19
radius of bubble, r = 0.02m
surface tension, T = 0.03N/m
Work required = surface area×surface tension
surface area = 4πr²
number of surfaces = 2
⇒ S = 2×4×3.14×0.02² = 0.01 m²
Work = 0.01×0.03 = 0.0003 J = 3×10⁻⁴ J
surface tension, T = 0.03N/m
Work required = surface area×surface tension
surface area = 4πr²
number of surfaces = 2
⇒ S = 2×4×3.14×0.02² = 0.01 m²
Work = 0.01×0.03 = 0.0003 J = 3×10⁻⁴ J
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