find the work which must be done to increase the velocity of an object of mass B/y from 2m/s to 6m/s.
Verma1111:
please tell me the mass
given nhi hh
hmm....
Answers
Answered by
2
K.E1 = 1/2m2×2
= 2m
K.E2= 1/2m6×6
=18m
Work Done required= K.E2 -K.E1
= 18m-2m
= 16m
Hence 16 m work is required to done
= 2m
K.E2= 1/2m6×6
=18m
Work Done required= K.E2 -K.E1
= 18m-2m
= 16m
Hence 16 m work is required to done
Answered by
6
Heya.....!!
We know that , WORK DONE = CHANGE IN KINETIC ENERGY .
i.e. WD = ∆KE .
KE1 = 1/2m×v^2
» 1/2×m×4
➡ 2m
KE2 = 1/2m×v^2
» 1/2×m×36
➡ 18m.
Work done = KE1 - KE2 »» 18m -2m
➡➡ 16m , is the required answer .
HOPE IT HELPS U
We know that , WORK DONE = CHANGE IN KINETIC ENERGY .
i.e. WD = ∆KE .
KE1 = 1/2m×v^2
» 1/2×m×4
➡ 2m
KE2 = 1/2m×v^2
» 1/2×m×36
➡ 18m.
Work done = KE1 - KE2 »» 18m -2m
➡➡ 16m , is the required answer .
HOPE IT HELPS U
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