Question

Find the work which must be done to increase the velocity of an object of mass 8 kg from 2 m/s to 6 m/s ?

Answer 1

From work energy theorem, change in kinetic energy is equals to work done.
1/2×8×(6^2-2^2) =work

Answer 2

The amount of work done during this period is 128 J.

Explanation:

Given that,

Mass of the body, m = 8 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 6m/s

To find,

Amount of work done.

Solution,

According to work energy theorem, the work done by an object is equal to the change in its kinetic energy. It is given by :

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 8((6)^2-(2)^2)$

W = 128 J

So, the amount of work done during this period is 128 J. Hence, this is the required solution.

Learn more

Work energy theorem

https://brainly.in/question/13849042