Math, asked by maanyaj06, 2 months ago

find the wrong number in given series: 4,10,18,34,74

Answers

Answered by Anonymous
2

Answer:

One possible answer is:

6–4 = 2 = 2^1

10–6 = 4 = 2^2

18–10 = 8 = 2^3

2,4,8 are all powers of 2. 2^n

2^4 = 16

18+16 = 34

34 is one possible solution.

The difference between the first term(4) and the second term(6) is (6–4)=2

The difference between the second term(6) and the third term(10) is (10–6)=4

The difference between the third term(10) and the fourth term(18) is (18–10)=8

Do you see the pattern, the difference is doubled after every operation, so the next difference would be (8*2)=16

Let X be the next number in the sequence..

X-18= 16

X= 16+18

X= 34

so, 72 is odd one

Answered by king202032123456
0

Answer:

6, 10, 18, 34, ?

6+4=1

10+(4×2)=18

18+(8×2)=34

34+(16×2)=66

∴ the answer is 66.

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