Question

Find the wrong number in the series 2, 6, 15, 31, 56, 93.

Answer 1

Answer:

31

Step-by-step explanation:

Answer 2

Given:

We have given a series of numbers which is 2,6,15,31,56,93.

To Find:

We have to find the wrong number in the given series?

Step-by-step explanation:

      We have series of numbers 2,6,15,31,56,93

       First of all we find the particular pattern of given series.

• From observing the series we get all the numbers are in the series are in increasing order. Thus, we will try to find the difference of the given consecutive numbers.
• The difference of first and second numbers is 6-2=4
• The difference of second and third numbers is 15-6=9
• The difference of third and fourth numbers is 31-15=16
• The difference of fourth and fifth numbers is 56-31=25
• The difference of fifth and sixth numbers is 93-56=37
• Now we can observe the pattern of differene of numbers is

       4,9,16,25,37 which can be also written as

       $4=2^2,9=3^2,16=4^2,25=5^2$

• But we are not able to write 37 as a whole square form but in the given series there is pattern of differnece of whole square

       $6=2^2+2\\15=3^2+6\\31=4^2+15\\56=5^2+31\\6^2+56=92$

• Hence the last term should be 92.

Thus, the wrong term is 92.