Find the x . (4/9)* × (2/3)' = 8/27.
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x in (-oo:+oo)
(4/9)*x = 8/27 // - 8/27
(4/9)*x-(8/27) = 0
(4/9)*x-8/27 = 0
4/9*x-8/27 = 0 // + 8/27
4/9*x = 8/27 // : 4/9
x = 8/27/4/9
x = 2/3
x = 2/3
(4/9)*x = 8/27 // - 8/27
(4/9)*x-(8/27) = 0
(4/9)*x-8/27 = 0
4/9*x-8/27 = 0 // + 8/27
4/9*x = 8/27 // : 4/9
x = 8/27/4/9
x = 2/3
x = 2/3
myra251:
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