Question

Find the x-and y-intercepts of the following equations.

2x + 3y = 12​

Answer 1

Answer:

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Step-by-step explanation:

2x + 3y = 12

Put the value of x = 0

2 × 0 + 3y = 12

3y = 12

3y/3 = 12/3

y = 4

Therefore, y-intercept = (0, 4)

Now, put the value of y = 0

2x + 3 × 0 = 12

2x = 12

2x/2 = 12/2

x = 6

Therefore, x-intercept = (6, 0)

follow me !

Answer 2

Given data

2x + 3y = 12

we know from equation of straight line

x/a + y/b = 1

p(a,b)

Now from above equation

2x/12 + 3y/12 = 1

X/6 + y/4 = 1

point p(6,4)